0=-16t^2+352t-968

Solution for 0=-16t^2+352t-968 equation:

0=-16t^2+352t-968

We move all terms to the left:

0-(-16t^2+352t-968)=0

We add all the numbers together, and all the variables

-(-16t^2+352t-968)=0

We get rid of parentheses

16t^2-352t+968=0

a = 16; b = -352; c = +968;
Δ = b2-4ac
Δ = -3522-4·16·968
Δ = 61952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61952}=\sqrt{30976*2}=\sqrt{30976}*\sqrt{2}=176\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-352)-176\sqrt{2}}{2*16}=\frac{352-176\sqrt{2}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-352)+176\sqrt{2}}{2*16}=\frac{352+176\sqrt{2}}{32}
$